This may be a very basic question about awk to handle exponential.
My input line is:
1.047788047990001417e+02 2.931134551062188009e+01 3.669999999999999929e+00
I want to add -1000 at third position but in exponential format, so first I convert the format.
dept=$(echo -1000 | awk '{printf "%.7e\n", $1}')
But when I try to insert it into the above line using cat and awk, it converts back to normal integers.
cat $line | awk '{print $1 ,$2 ,'$dept', $3}'
I got this output:
1.048020560949027811e+02 2.976214868620721887e+01 -1000 6.065999999999999837e+00
May you please indicate that where I am doing something wrong or how I can correct it? Besides this, is there any option to limit the 7 decimal numbers before e?
For example ideally expected output should be like this:
1.0480205e+02 2.9762148e+01 -1.0000000e+03 6.0659999e+00
Integers are printed as integers by default, even if you input it with exponential notation. If you want it formated, use printf().
cat "$line" | awk -v dept=-1.0000000e+03 '{printf("%e %e %e %e\n", $1, $2, dept, $3)}'
Use the -v option to turn a shell variable into an awk variable, rather than substituting the variable into the awk script.