I'm using ubuntu and have installed ImageMagick
identify -version
gives:
Version: ImageMagick 6.9.10-23 Q16 x86_64 20190101 https://imagemagick.org
Copyright: © 1999-2019 ImageMagick Studio LLC
License: https://imagemagick.org/script/license.php
Features: Cipher DPC Modules OpenMP
Delegates (built-in): bzlib djvu fftw fontconfig freetype jbig jng jpeg lcms lqr ltdl lzma openexr pangocairo png tiff webp wmf x xml zlib
I tried:
exec('magick img.jpg ( -clone 0 -fill white -colorize 100 ) ( -clone 0 -color-threshold "gray(251)-gray(254)" ) -compose over -composite -quality 80% result.jpg', $output, $return_var);
echo '<pre>' , var_dump($output) , '</pre>';
also convert and magick convert instead of magick
then according to this answer I opened /etc/ImageMagick-6/policy.xml
and changed <policy domain="coder" rights="none" pattern="PDF" /> to <policy domain="coder" rights="read|write" pattern="PDF" />
but still doesn't work and $output always returns empty array
PS: I don't want to use the PHP extension, already did and it has some flaws
Please do some testing in Imagemagick with PHP to see what your versions are. Please provide any messages that come back for each.
<?php
echo "<pre>";
system("type -a convert");
echo "</pre>";
?>
<?php
exec("magick -version",$out,$returnval);
foreach($out as $text)
{echo "$text<br>";}
?>
Does this work?
<?php
exec('magick img.jpg \( -clone 0 -fill white -colorize 100 \) \( -clone 0 -color-threshold "gray(251)-gray(254)" \) -compose over -composite -quality 80% result.jpg 2>&1',$out,$returnval);
foreach($out as $text)
{echo "$text<br>";}
?>
What messages do you get?