I'm trying to figure out an algorithm to have all possible combinations and permutations of size k
from an array of size n
.
Let's have an example:
Input:
n = 3 => [1, 2, 3]
Output should be:
k = 1 => [[1], [2], [3]]
k = 2 => [[1, 2], [1, 3], [2, 3], [2, 1], [3, 1], [3, 2]]
k = 3 => [[1, 2, 3], [1, 3, 2], [2, 1, 3], [2, 3, 1], [3, 1 ,2], [3, 2, 1]]
I started by looking at the QuickPerm Algorithm but it gives all possible permutations for the size of the array:
If we go back to our example, the QuickPerm algorithm gives this output:
[[1, 2, 3], [1, 3, 2], [2, 1, 3], [2, 3, 1], [3, 1 ,2], [3, 2, 1]].
Your task (all permutations of all combinations) can be easily solved using regular recursive function (as I did below) without any fancy algorithm.
#include <vector>
#include <functional>
#include <iostream>
void GenCombPerm(size_t n, size_t k, auto const & outf) {
std::vector<bool> used(n);
std::vector<size_t> path;
std::function<void()> Rec =
[&]{
if (path.size() >= k) {
outf(path);
return;
}
for (size_t i = 0; i < used.size(); ++i) {
if (used[i])
continue;
used[i] = true;
path.push_back(i);
Rec();
path.pop_back();
used[i] = false;
}
};
Rec();
}
int main() {
std::vector<size_t> a = {1, 2, 3};
GenCombPerm(a.size(), 2, [&](auto const & v){
std::cout << "[";
for (auto i: v)
std::cout << a[i] << ", ";
std::cout << "], ";
});
}
Output:
[1, 2, ], [1, 3, ], [2, 1, ], [2, 3, ], [3, 1, ], [3, 2, ],