import itertools
x = [[0,0],[1,1]]
list(itertools.product(x,x))
produces
[([0, 0], [0, 0]), ([0, 0], [1, 1]), ([1, 1], [0, 0]), ([1, 1], [1, 1])]
But I'm looking for something that produces
[[0, 0, 0, 0], [0, 0, 1, 1], [1, 1, 0, 0], [1, 1, 1, 1]]
In that case, you can easily do without using itertools
, using list comprehension:
x = [[0, 0], [1, 1]]
output = [a + b for b in x for a in x]
# [[0, 0, 0, 0], [1, 1, 0, 0], [0, 0, 1, 1], [1, 1, 1, 1]]
the equivalent without list comprehension would be:
output = []
for a in x:
for b in x:
output.append(a + b)
print(output)