I am implementing this code in my discord bot, where I want to be able to generate unique numbers from 1 to 10 (as suggested above) whenever I input a single command.
Turns out that the values sometimes are repeated. Therefore I was suggested to add an array (used[ ]) and a loop in order to check every time if the value has been generated already.
Random random = new Random();
int[] used = new int[10];
int rng = 0;
while (!used.Contains(rng))
{
rng = random.Next(1, 10);
}
/*
I wish to store the generated value "rng" to the "used" array.
e.g.
used[0] = rng
used[1] = rng
used[2] = rng
etc.
*/
Console.WriteLine("The number generated is " + Convert.ToString(rng));
However, I don't know how to constantly add values to an array in an arranged order. (as seen by the commentations above)
In a more simple way, For 10 times I want the system to generate a number, and those numbers are randomly picked out of [1,10] and only once. If all the numbers have been generated once, all are free to be generated again.
Sorry for my bad interpretation. I have refined it with the comments that everyone has contributed.
Here is a solution, that shuffles the values and returns each value until the list is exhausted, then starts all over:
int[] GenerateNewArray(int n)
{
// Define an array of values we wish to return and populate it
int[] baseValues = Enumerable.Range(1, n).ToArray();
Random rnd=new Random();
// Shuffle the array randomly using Linq
return baseValues.OrderBy(x => rnd.Next()).ToArray();
}
void Main()
{
int nNumbers = 10;
while (true)
{
// Generate a new randomized array
var values = GenerateNewArray(nNumbers);
// Print each value
for (int i=0;i<nNumbers;i++)
{
Console.WriteLine($"The number generated is {values[i]}");
}
}
}
EDIT Parameterized the number of unique values.