I was given this question to solve. My code outputs 316 but some suggest 345 is a correct answer. I don't know if my code works properly or not since I use the Sakamoto algorithm to calculate the weekday of a given day, month, and year. Since the actual date for 24 March, 2002 is Sunday instead of Wednesday (0 is Sunday ... 6 is Saturday). I add 3 (as a constant variable) in an algorithm. This is where I am a bit hesitant whether I make the right choice or not. However, I think that a shift does not affect anything so is this supposed to work?? Alternatively, I could set the weekday to Tuesday instead of Friday without any constant.
This is my code:
#include <stdio.h>
#include <math.h>
int howManyDays() {
int sakamoto();
int starting_weekday = 3;
int result = sakamoto(24,3,2002,0);
int constant = starting_weekday - result;
int calculated_year = 1801;
int calculated_month = 1;
int count = 0;
do {
int calculated_weekday = sakamoto(5, calculated_month, calculated_year, constant);
//int calculated_weekday = (calculated_day+constant+day_in_months[calculated_month-1]) % 7;
if (calculated_weekday == 5) {
count += 1;
}
calculated_month += 1;
if (calculated_month == 12) {
calculated_month = 1;
calculated_year += 1;
}
} while(!(calculated_month == 1 && calculated_year == 2001));
return count;
}
int sakamoto(int d, int m, int y, int c) {
int offset[] = {0, 3, 2, 5, 0, 3, 5, 1, 4, 6, 2, 4}; // 0->Sunday ... 2->Tuesday ... 6->Saturday
y -= m < 3;
return (y + y / 4 - y / 100 + y / 400 + offset[m - 1] + d + c) % 7;
}
int main() {
int a = howManyDays();
printf("result: %d", a);
}
Could anyone confirm whether what I think is correct or completely false?? Thanks in Advance, Hope you have a wonderful time :)
Your months range from 1 to 11. Since you're not counting Fridays in December, your results are off by about 1/12th and indeed 345*11/12 = 316.25.