Might just be an edge case but I extracted a zip file to a directory using the zip file module. When extracting, zip file names the directory it extracts to.
If there is a way I get to specify the name of the folder Zip file creates to extract the files to? I am hitting an error because I am using the same folder zipped up to test zip file and it keeps using the old folder name which already exists so it throws an error. Here is my code:
orginalFolderName = jobFolder + name
with zipfile.ZipFile(directory,"r") as zip_ref:
zip_ref.extractall(jobFolder)
os.rename(orginalFolderName, newFoldername)
directory = newFoldername
with zipfile.ZipFile(filepath) as z:
z.extractall(dest_folder)
filepath - Complete path of zipfile
dest_folder - destination folder