I have the following question. bbox2 is a list of data points, and as you see every bbox2[k - 1::k] element is 0.
save_text = [image_path]
bbox2 = [126,0,178,38,0,254,415,316,472,0,390,292,423,326,0]
bbox2 = str(bbox2).replace(' ', '')
save_text.append(bbox2)
with open('output.txt', 'a') as file:
file.write(' '.join(map(str, save_text)).replace('[', '').replace(']', '') + '\n')
Now please look at the output. The output I am getting is:
output:
DSC07368_053.jpg 126,0,178,38,0,254,415,316,472,0,390,292,423,326,0
So now my question is how can I write this text file like the expected output.
Expected output:
DSC07368_053.jpg 126,0,178,38,0 254,415,316,472,0 390,292,423,326,0
If I use another .replace(',0,',',0 ') then there is a problem because it is replacing all of it but I need the space after each bbox2[k - 1::k] element instead of a comma.
You could use while-loop with bbox2[:k] and bbox2[k:] to convert list to 2D list
bbox2 = [126,0,178,38,0,254,415,316,472,0,390,292,423,326,0]
k = 5
list2D = []
while bbox2:
list2D.append(bbox2[:k]) # beginnig elements
bbox2 = bbox2[k:] # rest of list
print(list2D)
Result:
[
[126, 0, 178, 38, 0],
[254, 415, 316, 472, 0],
[390, 292, 423, 326, 0]
]
And this list is simply to convert to list of strings
substrings = ["DSC07368_053.jpg"]
for sublist in list2D:
text = ",".join( map(str, sublist) )
substrings.append(text)
print(substrings)
Result:
[ "DSC07368_053.jpg", "126,0,178,38,0", "254,415,316,472,0", "390,292,423,326,0" ]
And now you need only " ".join() to convert to single string
result = " ".join(substrings)
Result:
DSC07368_053.jpg 126,0,178,38,0 254,415,316,472,0 390,292,423,326,0
Full code can be reduced to
bbox2 = [126,0,178,38,0,254,415,316,472,0,390,292,423,326,0]
k = 5
substrings = ["DSC07368_053.jpg"]
while bbox2:
sublist = bbox2[:k] # beginnig elements
bbox2 = bbox2[k:] # rest of list
text = ",".join( map(str, sublist) )
substrings.append(text)
result = " ".join(substrings)
print(result)
But version with while-loop destroys original bbox2 and to keep original bbox2 you would have to duplicate it with bbox2.copy().
Or it is situation when range(len()) can be useful.
bbox2 = [126,0,178,38,0,254,415,316,472,0,390,292,423,326,0]
k = 5
substrings = ["DSC07368_053.jpg"]
for x in range(0, len(bbox2), k):
sublist = bbox2[x:x+k]
text = ",".join(map(str, sublist))
substrings.append(text)
result = " ".join(substrings)
print(result)
It can be use to create useful function slicer()
def slicer(data, k):
for x in range(0, len(data), k):
yield data[x:x+k]
# ---
bbox2 = [126,0,178,38,0,254,415,316,472,0,390,292,423,326,0]
k = 5
substrings = ["DSC07368_053.jpg"]
for sublist in slicer(bbox2, k):
text = ",".join(map(str, sublist))
substrings.append(text)
result = " ".join(substrings)
print(result)