With the following string saved in variable "start":
user stuff here 5
user banana1 pswd 4
user lemon2 pswd 5
mumbo jumbo 12333 3
user h3lp pswd 8
What regex will grab the three digits(4,5,8) after 'pswd' preceded by a random string and 'user'? New to groovy matching. I attempted this (username.*secret).\d
would ideally like to perform something like this, where the matches can then be accessed in an array
def pattern = ~/\S+er\b/
def matcher = "My code is groovier and better when I use Groovy there" =~ pattern
assert matcher[0..-1] == ["groovier", "better"]
You can use
/\buser\s+\S+\s+pswd\s+(\d+)/
See the regex demo. Details:
\b - a word boundaryuser - a user word\s+ - one or more whitespaces\S+ - one or more non-whitespaces (some word)\s+ - one or more whitespacespswd - a pswd word\s+ - one or more whitespaces(\d+) - Group 1: one or more digits.See the Groovy demo:
String s = "user stuff here 5\nuser banana1 pswd 4\nuser lemon2 pswd 5\nmumbo jumbo 12333 3\nuser h3lp pswd 8"
def re = /\buser\s+\S+\s+pswd\s+(\d+)/
def res = (s =~ re).collect { it[1] }
print(res)
Output:
[4, 5, 8]