I need to convert string to time in hours format. I tried using the below But I didn't get the results that I expect.
inp_string = "70:30:00"
print(datetime.strptime(inp_string, "%H:%M:%S").time())
For this I'm getting the following error:
ValueError: time data '70:30:00' does not match format '%H:%M:%S'
If I enter the value of hours below 24 I'm getting good results;
new = '23:30:00'
print("value:",datetime.strptime(new, "%H:%M:%S").time())
print(type(datetime.strptime(new, "%H:%M:%S").time()))
output
value: 23:30:00
<class 'datetime.time'>
Like this, I have to convert a string into time format where the hours are greater than 24.
You need to write your own parser to convert your str to timedelta (or find a library that does this for you).
Assuming your duration is always like HH:MM:SS, you can use something like this:
import datetime
def parse_duration(s):
return list(map(lambda x: int(x), s.split(":")))
inp1 = "70:30:00"
[h1, m1, s1] = parse_duration(inp1)
d1 = datetime.timedelta(hours=h1, minutes=m1, seconds=s1)
inp2 = "00:30:00"
[h2, m2, s2] = parse_duration(inp2)
d2 = datetime.timedelta(hours=h2, minutes=m2, seconds=s2)
res = d1 + d2
# Format res however you like