How to skip a line every two lines starting by skipping the first line?

Question

Here's my code : ls -lt | sed -n 'p;n'

That code makes me skip from a line to another when listing file names but doesn't start by skipping the first one, how to make that happen?

Here's an exemple without my code to skip to make it clear:

And here's an exemple of when I use the skip code:

Answer 1

You have to invert your sed command: it should be n;p instead of p;n:

Your code:

for x in {1..20}; do echo $x ; done | sed -n 'p;n'

1
3
5
7
9
11
13
15
17
19

The version with sed inverted:

for x in {1..20}; do echo $x ; done | sed -n 'n;p'

Output:

2
4
6
8
10
12
14
16
18
20