How to get specific values from a dictionary using list comprehension and modify them?

Question

Can someone help and kindly advise how Can I get specific values from this dictionary (Using list comprehension) and

1. square the values only,
2. change every string value, so it starts with upper case?

items_list = {'a': 3, 'b':6, 'c': 'short', 'h': 'example', 'p': 77}

So, the output needs to be:

9, 36, 5929
Short, Example

Answer 1

(Python):

items_list = {'a': 3, 'b': 6, 'c': 'short', 'h': 'example', 'p': 77}

lst = [v ** 2 if isinstance(v, (int, float)) else v.capitalize() for v in
       items_list.values()]

print(lst)

output:

[9, 36, 'Short', 'Example', 5929]

The exact output that you showed can not be produced using single list comprehension, because the iteration is in order.