Android Launch foreign application from my own

Question

I am trying to get the following code to execute:

Intent intent = new Intent(Intent.ACTION_MAIN); 
intent.addCategory(Intent.CATEGORY_HOME);
intent.setComponent(new ComponentName(" **Home package** "," **Home class** "));
                  startActivity(intent);

Essentially I am looking for a way to specifically target and load the exact, original, home application.

Answer 1

EDIT: SOLUTION:

        PackageManager pm=getPackageManager();
        Intent main=new Intent(Intent.ACTION_MAIN, null);

        main.addCategory(Intent.CATEGORY_HOME);
        List<ResolveInfo> launchables=pm.queryIntentActivities(main, 0);

        Collections.sort(launchables,
                         new ResolveInfo.DisplayNameComparator(pm));

        int launcher_flag = findLauncherApp(launchables);

        ResolveInfo launchable = launchables.get(launcher_flag);

        ActivityInfo activity=launchable.activityInfo;
        ComponentName name=new ComponentName(activity.applicationInfo.packageName,
                                             activity.name);
        Intent i=new Intent(Intent.ACTION_MAIN);

        i.addCategory(Intent.CATEGORY_LAUNCHER);
        i.setFlags(Intent.FLAG_ACTIVITY_NEW_TASK |
                    Intent.FLAG_ACTIVITY_RESET_TASK_IF_NEEDED);
        i.setComponent(name);

        startActivity(i);

Where findLaucherApp() turns the List into an array of strings and interrogates each one to see if it contains "com.android.launcher2" and then returns its id.