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regexerlangpython-re

Erlang regular expression to replace all occurrences

I have given the following string:

S = "I want to replace {something} and {this}, too"

I want to replace everything inside curly brackets. (Brackets included). So that I get:

"I want to replace X and X, too"

I have some trouble understanding the re module in the official erlang docs. What I managed so far with

re:replace(S, "(\{.*?\})", "X", [{return, list}]).

is to get:

"I want to replace X and {this}, too"

How can I use re:replace so that all occurrences of the pattern are replaced?

Thank you!

Solution

  • I solved it thanks to @vinesh by providing the global option like:

    re:replace(S, "(\{.*?\})", "X", [global, {return, list}]).