public static int[] booleanToBinary(boolean[] b) {
int[] arr = new int[b.length];
for(int i = 0; i < b.length; i++) {
if(b[i] == true) {
arr[i] = 1;
}
else{arr[i] = 0;};
}
return arr;
}
public static int binaryToInt(boolean[] b) {
int[] a = booleanToBinary(b);
String c = Arrays.toString(a);
System.out.println(c);
int decimal = Integer.parseInt(c, 2);
System.out.println(decimal);
return decimal;
}
public static void main(String[] args) {
boolean[] test = {false, true, false, true};
System.out.println(Arrays.toString(booleanToBinary(test)));
System.out.println(binaryToInt(test));
}
Blockquote I'm trying to turn the binary value into an Integer value, and I'm trying to do that using the binaryToInt method, and an NumberExceptionFormat is happening, I know that this error happens when java cannot convert a String into an Integer, can someone help me to fix this this error
To convert a list of booleans to an int equivalent, try it like this. No need to use any strings or integer parsing methods.
// 100111 the value = 39
boolean[] b = {true, false, false, true, true, true};
int v = binaryToInt(b);
System.out.println(v);
prints
39
public static int binaryToInt(boolean[] bools) {
int decimal = 0;
for (boolean b : bools) {
decimal = decimal * 2 + (b ? 1 : 0);
}
return decimal;
}
Similarly, to convert an array of booleans to an array of 1's or 0's.
public static int[] booleanToBinary(boolean[] bools) {
int[] arr = new int[bools.length];
int i = 0;
for (boolean b : bools) {
arr[i++] = b ? 1 : 0;
}
return arr;
}
Note if you want to just convert your boolean array into a binary string, this will work.
public static String booleanToBinaryString(boolean[] bools) {
int[] arr = new int[bools.length];
String result = "";
for (boolean b : bools) {
result += b ? 1 : 0;
}
return result;
}
System.out.println(booleanToBinaryString(b));
prints
100111