Consider
ex1 = quote(fn(NULL))
and suppose I wish to make ex1
equals to fn(lhs=rhs)
in expression form, how do I do that?
since
ex1[[2]] = quote(lhs=rhs)
gives ex1 = fn((lhs=rhs))
and I can't seem to get rid of the parenthesis.
You can do
ex1 <- quote(fn(NULL))
ex1
#> fn(NULL)
ex1[[2]] <- quote(rhs)
names(ex1)[2] <- "lhs"
ex1
#> fn(lhs = rhs)
Created on 2022-01-29 by the reprex package (v2.0.1)