I am trying to zip a folder using python. The following command works from command prompt:
7z a C:\\Temp\\ C:\\Temp\\
But the following only show an error code of 1:
os.system("7z a C:\\Temp\\ C:\\Temp\\")
subprocess.call(["7z a C:\\Temp\\ C:\\Temp\\"], shell=True)
os.system("C:\Program Files\7-Zip\7z.exe a C:\\Temp\\ C:\\Temp\\")
Calling exe's with full path to them works for me well with the above approaches. Could anyone suggest a solution?
Try:
os.system("C:\\"Program Files\"\7-Zip\7z.exe a C:\\Temp\\ C:\\Temp\\")
add => "
in (program file section)