I have the following problem in Java. I am using an encryption algorithm that can produce negative bytes as outcome, and for my purposes I must be able to deal with them in binary. For negative bytes, the first or most significant bit in the of the 8 is 1. When I am trying to convert binary strings back to bytes later on, I am getting a NumberFormatException
because my byte is too long. Can I tell Java to treat it like an unsigned byte and end up with negative bytes? My code so far is this:
private static String intToBinByte(int in) {
StringBuilder sb = new StringBuilder();
sb.append("00000000");
sb.append(Integer.toBinaryString(in));
return sb.substring(sb.length() - 8);
}
intToBinByte(-92); // --> 10100100
Byte.parseByte("10100100", 2) // --> NumberFormatException
Value out of range. Value:"10100100" Radix:2
Is there a better way to parse signed Bytes from binary in Java? Thanks in advance!
I have written the following function to solve the problem:
private static byte binStringToByte(String in) {
byte ret = Byte.parseByte(in.substring(1), 2);
ret -= (in.charAt(0) - '0') * 128;
return ret;
}