I'm trying to build a regex that stop when a line is equal to "--- admonition".
For example, I have :
??? ad-question Quels sont les deux types de bornages ?
Il y en a deux :
- Le bornage amiable.
- Le bornage judiciaire.
test
--- admonition
I can have the same capture format multiple time on a page.
I want to retrieve (in every match) in a first group :
Quels sont les deux types de bornages ?
and in a second :
Il y en a deux :
Le bornage amiable.
Le bornage judiciaire.
test
I tried :
^\?{3} ad-question {1}(.+)\n*((?:\n(?:^[^#].{0,2}$|^[^#].{3}(?<!---).*))+)
or
^\?{3} ad-question {1}(.+)\n*((?:\n(?:^[^\n#].{0,2}$|^[^\n#](?<!----).*))+)
but it didn't stop at "\n--- admonition" and it took the new line between the two group.
Is someone can help me build this regex ?
ps : I must have a new line between the two group and between group 2 and "---- admonition". So these lines must be avoid in the groups.
Thanks for your help.
If you want 2 capture groups without matching the newlines in between the groups, but there must be at least a whole empty line in between the groups:
^\?{3} ad-question (.+)\n{2,}((?:(?!---).*\n)*?)\n+---
The pattern matches:
^ Start of string\?{3} ad-question Match ??? ad-question (.+) Capture group 1, match the whole line\n{2,} Match 2 or more newlines, so that there is at least an empty line in between( Capture group 2
(?:(?!---).*\n)*? Repeat as least as possible matching all lines and the newline, that do not start with ---) Close group 2\n+--- Match 1 or more newlines and ---If there should be at least a single newline present:
^\?{3} ad-question (.+)\n+((?:(?!---).*\n)*?)\n*---