Return specific values from a nested dictionary with a generator function

Question

I have a list of dict containing nested dict which looks like below. I would like to use generators and yield to go over reviews list of dict and return all rating given a specific user value. For example "user" : "A11" has two rating records. I would like to have these returned as dict.

data = [{ "product_id" : "123",
    "size" : "L",
    "color" : "blue",
    "reviews" : [
        { "user" : "A11", "rating" : "score1" },
        { "user" : "Z99", "rating" : "score" }] },

    { "product_id" : "987",
    "size" : "M",
    "color" : "red",
    "reviews" : [
        { "user" : "A11", "rating" : "score2" },
        { "user" : "X55", "rating" : "score" }] }
    ]

I have the following generator but it is basically returning all rating values regardless of the user. How can I make the function to filter the values to a specific user ?

def user_rating(nest, kv):
    if isinstance(nest, list):
        for i in nest:
            for x in user_rating(i, kv):
                yield x
    elif isinstance(nest, dict):
        if kv in nest:
            yield nest[kv]
        for j in nest.values():
            for x in user_rating(j, kv):
                yield x

print(list(user_rating(data, 'rating')))

Answer 1

A little modify should be enough:

def user_rating(nest, kv):
    if isinstance(nest, list):
        for i in nest:
            yield from user_rating(i, kv)
    elif isinstance(nest, dict):
        if nest.get('user') == kv: # <----- here
            yield nest # <---- and here
        for j in nest.values():
            yield from user_rating(j, kv)
                
print(list(user_rating(data, 'A11')))
#[{'user': 'A11', 'rating': 'score1'}, {'user': 'A11', 'rating': 'score2'}]

Btw you can use yield from to ... well, yield from another generator instead of using a for loop