How to launch Amazon app using product link in flutter?

Question

I want to open Amazon App when someone press the elevated button. I am using url_launcher package and using affiliate product link.

ElevatedButton(
      onPressed: () {
        launch("https://www.amazon.com/");
      },
      child: Text("amazon"),
    ),

Answer 1

Try below code hope its helpful to you.

You must use url_launcher package from here add this dependency in your pubspec.yaml file

You can refer my answer here also for open app from URL

create one widget

InkWell(
      hoverColor: Colors.transparent,
      child: Image.network(
        'https://upload.wikimedia.org/wikipedia/commons/d/de/Amazon_icon.png',
        width: 70,
        height: 70,
      ),
      onTap: () => amazon(),
    )

Create ontap function

amazon() async {
    const url =
        'https://www.amazon.com/';// or add your URL here
    if (await canLaunch(url)) {
      await launch(url);
    } else {
      throw 'Could not launch $url';
    }
  }