How can I prevent the result from being a complex number? (Cube root of -27)

Question

I've figured out the following solution (probably not that hard anyway):

n1, n2 = -27, 3
root = ( n1 ** (1/n2))
print(root)

(1.5000000000000004+2.598076211353316j)

Unless I'm making a very dumb mistake, it should print -3 instead.

Answer 1

To find the real cubic root of a negative number, use:

number = -27
if number > 0:
    real_root = number ** (1/3)
elif number < 0:
    real_root = - (abs(number) ** (1/3))
elif number == 0:
    real_root = 0