I am working on numeric derivation, and experiment with how small of a value Δx can be in python. I have understood that using np.linspace(0, 1, 1000)
creates values that are rounded to 0. To prevent my otherwise clean output window from showing error messages, I have tried this:
try:
#do the numeric derivation
except RuntimeWarning:
#do something else
else:
#the actual function of the program
But when I run I still get the following message:
RuntimeWarning: invalid value encountered in double_scalars
So, is there a way for me to except that exact warning? I have also tried to except the entire warning text (like, from Runtime to _scalars), but nothing works.
Here is my program
import numpy as np
import matplotlib.pyplot as plt
xValue = np.linspace(0, 5, 5)
ΔxValues = np.linspace(0, 1, 1000)
def f(x):
return x**2 + 2*x + 4
def fDerN(x, Δx):
return (f(x + Δx) - f(x))/Δx
def fDerA(x):
return 2*x + 2
difference1, difference2, difference3, difference4, difference5= [], [], [], [], []
for Δx in ΔxValues:
try:
fDerN(1, Δx)
fDerN(2, Δx)
fDerN(3, Δx)
fDerN(4, Δx)
fDerN(5, Δx)
except RuntimeWarning:
hasBeenWarning = True #Just to have an indented piece of code
else:
difference1.append(abs(fDerN(1, Δx) - fDerA(1)))
difference2.append(abs(fDerN(2, Δx) - fDerA(2)))
difference3.append(abs(fDerN(3, Δx) - fDerA(3)))
difference4.append(abs(fDerN(4, Δx) - fDerA(4)))
difference5.append(abs(fDerN(5, Δx) - fDerA(5)))
plt.plot(ΔxValues, difference1, label="x = 1")
plt.plot(ΔxValues, difference2, label="x = 2")
plt.plot(ΔxValues, difference3, label="x = 3")
plt.plot(ΔxValues, difference4, label="x = 4")
plt.plot(ΔxValues, difference5, label="x = 5")
plt.title("Difference between numeric and algebraic derivation for different values of x og Δx")
plt.grid()
plt.legend()
plt.show()
If this works, it is because I translated it to english.
You define ΔxValues
as np.linspace(0, 1, 1000)
. The problem is that in
def fDerN(x, Δx):
return (f(x + Δx) - f(x))/Δx
you divide by Δx
. The first number in ΔxValues
is 0, which will obviously cause a division by 0 error.
print(ΔxValues[0])
# 0.0
Circumvent this by redefining ΔxValues
, or by simply using ΔxValues[1:]
To catch the warning in your try/except as if it were an error, you can use filterwarnings from the warnings module.
import warnings
warnings.filterwarnings("error")