I'm trying out multiple inheritance and would like to get the hang of it without using packages like Moose
to sort out the issue behind the scenes.
I have two base classes, Left
and Right
, in a "broken" diamond:
Left Right
\ /
Multi
They both implement an overload
for ""
. When calling a method, below named perform
, in any of the base classes, those methods are supposed to use this overload to print a representation of that part of the object. Multi
implements perform
as so:
sub perform {
my $self = shift;
$self->Left::perform;
$self->Right::perform;
}
What happens is that both base classes perform
methods are called as they are supposed to, but when those methods call any other methods (like the ""
overload) it'll always be the one in Left
. However, if an instance of Right
is created separately (not as a part of Multi
) it'll call the correct method.
Here's what I've tried (in perl v5.26.1 and v5.32.1):
#!/usr/bin/perl
use strict;
use warnings;
package Left; #----------------------------------------------------------------
sub new {
my ($class, @args) = @_;
my $self = bless {}, $class;
return $self->_init(@args);
}
sub _init {
my $self = shift;
$self->{_leftval} = shift;
return $self;
}
sub value { shift->{_leftval}; }
use overload '""' => sub {
my $self = shift;
'Left(' . $self->value . ')';
};
sub perform {
my $self = shift;
print '# LEFT ' . $self . "\n";
}
package Right; #---------------------------------------------------------------
sub new {
my ($class, @args) = @_;
my $self = bless {}, $class;
return $self->_init(@args);
}
sub _init {
my $self = shift;
$self->{_rightval} = shift;
return $self;
}
sub value { shift->{_rightval}; }
use overload '""' => sub {
my $self = shift;
'Right(' . $self->value . ')';
};
sub perform {
my $self = shift;
print '# RIGHT ' . $self . "\n";
}
package Multi; #---------------------------------------------------------------
use parent -norequire, 'Left', 'Right' ;
sub new {
my ($class, @args) = @_;
my $self = bless {}, $class;
return $self->_init(@args);
}
sub _init {
my $self = shift;
$self->Left::_init(shift);
$self->Right::_init(shift);
return $self;
}
sub perform {
my $self = shift;
$self->Left::perform;
$self->Right::perform;
}
package main; #----------------------------------------------------------------
my $l = Left->new("a Left");
my $r = Right->new("a Right");
my $m = Multi->new("lEfT", "rIgHt");
$l->perform;
$r->perform;
print "---- and now a Multi ----\n";
$m->perform;
Expected output:
# LEFT Left(a Left)
# RIGHT Right(a Right)
---- and now a Multi ----
# LEFT Left(lEfT)
# RIGHT Right(rIgHt)
Actual output (note the last line):
# LEFT Left(a Left)
# RIGHT Right(a Right)
---- and now a Multi ----
# LEFT Left(lEfT)
# RIGHT Left(lEfT)
A virtual method is resolved based on the object's class, not the caller's namespace/package/class.
In Perl, whether a method is virtual or not isn't an intrinsic property. It depends on how it's called.
$o->method # Virtual method
Avoiding this require specifying the class
$o->Class::method
You don't want a virtual method call, so you'll need to change how you call the method.
package Left;
use overload '""' => \&to_string;
sub to_string {
my $self = shift;
'Left(' . $self->value . ')';
}
sub perform {
my $self = shift;
print '# LEFT ' . $self->Left::to_string() . "\n";
}
Except that's all wrong. If it was one method, this would make sense. But we're talking about every method. This is the air raid siren of red flags.
What we want here is composition, not inheritance. Multi IS A Left and IS A Right isn't correct. Rather, Multi HAS A Left and HAS A Right.
package Multi; #---------------------------------------------------------------
use parent -norequire, 'Left', 'Right' ;
sub new {
my ($class, @args) = @_;
my $self = bless {}, $class;
return $self->_init(@args);
}
sub _init {
my $self = shift;
$self->{ left } = Left ->new(shift);
$self->{ right } = Right->new(shift);
return $self;
}
sub perform {
my $self = shift;
$self->{ left }->perform;
$self->{ right }->perform;
}