I need to get an expression to get users in cisco which has not lower privileges 0 or 1. Users can be found in configuration file in the following way:
username myuser privilege 15 password 7 5345345345
So, I´m trying with expression:
(username.*privilege )(?!([01]))( password 7)
To get all lines with "username privilege" for any user name, followed by a group of characters that aren´t 0 or 1, and followed by "password" and other characters.
But testing in some online tester webpage i am not receiving the desired result. what am i doing wrong?
Thanks a lot
You can add a word boundary after [01]\b and when that assertion is true, you could still have to match the digits using [0-9]+
The pattern matches password 7 literally, but you could also use [0-9]+ here to match the digits.
.*\b(username.*privilege) (?![01]\b)[0-9]+ (password [0-9]+).*
Note that if you only want to match the whole line, you can omit the capture groups:
.*\busername.*?privilege (?![01]\b)[0-9]+ password [0-9].*