regexnotepad++substitution
Substitute one group with another group; Followup question
I'll be referring to this thread: Substitute one group with another group
What I'd like to do is to put a value of P1(y) in to P4(y),
with end result: (...) <P4 x="-0,36935" y="0,26315"/>
My previous question, being similar, seems to require a completely new approach. And unfortunately I couldn't find a reliable solution.
Example to work on: https://regex101.com/r/iua3p0/2
<P1 x="-0,36935" y="0,26315"/><P2 (...)/><P3 (..)/><P4 x="-0,36935" y="-0,40351"/>
<P1 x="4,64065" y="0,26315"/><P2 (...)/><P3 (..)/><P4 x="4,64065" y="-0,40351"/>
Solution
To put a value of P1(y) in to P4(y) on the same line, you could use:
<P1[^>]*\hy="([^"]+)"[^>]*>.*?<P4[^>]*\hy="\K[^"]+(?=[^>]*>)
The pattern matches:
<P1[^>]*Match<P1and optional chars other than>\hy="Match a space andy="([^"]+)Capture chars other than"in group 1"[^>]*>Match"and optional chars other than>and then match>.*?Match as few as possible chars<P4[^>]*\hy="Match<P4and optional char other than>and then match a space andy="\K[^"]+Clear the match buffer, and then match what you want to remove, in this case 1+ chars other than"(?=[^>]*>)Positive lookahead to assert a>to the right
And replace with group 1 using $1
See a regex demo.
Note that to not match across lines using the negated character class, you can exclude matching newlines using [^"\r\n] and [^>\r\n]*
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