I have a table that houses hotel ids and amenity ids. When a user chooses amenities i need to only pull hotels that have ALL of the chosen amenities. As of now it gets me all hotels that have at least one. How can i change this builder query to handle it so it does not include hotels that do not have all of them.
$builder = Hotels::query();
$builder->select('hotels.id','hotels'.'hotels_name')
$request_amenities = $request->amenities;
$builder->join('amenities_hotels', function ($join) use($request_amenities) {
$join->on('amenities_hotels.hotel_id', '=', 'hotel.id')
->whereIn('amenities_hotels.amenities_id', $request_amenities);
});
It's something like WhereAll
you need ...
you have to add whereHas
, for every Item in your array.
$builder = Hotels::query();
$builder->select('hotels.id', 'hotels' . 'hotels_name');
$request_amenities = $request->amenities;
if($request_amenities!=null)
{
for ($i = 0; $i < $this->count($request_amenities); $i++) {
$builder = $builder->whereHas('amenitiesHotels', function ($query) use ($i, $request_amenities) {
$query->where('amenities_hotels.amenities_id', $request_amenities[$i]);
});
}
see more about where in all in this question