I have two sparql querys , simplifying my problem :
query 1:
select ?letter ?number
-> results ({a1}{b2}{d4})
.... query 2:
select ?anotherletter ?anotherNumber
-> results ({b2}{c3})
How can i join the 2 querys to obtain the sum of the second column, maybe same values of a one lista couldnt be in the second. The result of the query has to be
{a,1}{b,4}{c,3}{d,4}
Is there a propper way to do that?
The solution that gives @UninformedUser worked:
select ?letter (sum(?number) as ?cnt) { {QUERY1} UNION {QUERY2} } group by ?letter
and yes, the variables should be the same in both UNION parts. – UninformedUser