How to combine 2 lists in such a way that each element in list 2 is combined with the elements in list 1 so that “a” combines with only one element in list 1 in each iteration then “b” combines with only two elements in the list 1 in each iteration.
list1= [1,2,3]
list2= [‘a’,‘b’,‘c’,‘d’,‘e’]
dict_list_2 = {‘a’ : 1 , ‘b’ : 2 , ‘c’ : 3 , ‘d’ : 4 , ‘e’ :5}
Expected Output: ('a',1) (a ,2 ) (a , 3) (b , 1 ,2) (b , 1 ,3) (b , 2 ,3) (b , 1 ,1) (b , 2 ,2) (b , 3 ,3) –
Assuming you want all combinations with replacement from list1:
import itertools
list1= [1,2,3]
list2= list("abcde")
dict_list_2 = {"a" : 1 , "b" : 2 , "c" : 3 , "d" : 4 , "e" :5}
[(letter,) + product
for letter in list2
for product in itertools.product(list1, repeat=dict_list_2[letter])]
# out:
[('a', 1),
('a', 2),
('a', 3),
('b', 1, 1),
('b', 1, 2),
('b', 1, 3),
('b', 2, 1),
('b', 2, 2),
('b', 2, 3),
('b', 3, 1),
('b', 3, 2),
('b', 3, 3),
('c', 1, 1, 1),
('c', 1, 1, 2),
('c', 1, 1, 3),
('c', 1, 2, 1),
...