I'm using Firebase Remote Config and with my current setup, the only way to make the config only released to user with correct version is by using regex.
I'm looking for a regex that match any version released later than A.B.C
So if new version is x.y.z then the following must be true for it to match:
(x > A) or {(x = A) and [(y > B) or ((y = B) and (z > C))]}
Real number example:
Match any version equal to or later than 1.1.7:
Match:
1.1.7
1.1.8
1.1.69
1.2.0
1.10.0
2.0.0
Don't match:
1.1.6
1.0.34
0.5.0
0.77.0
I have tried this regex: ^(([2-9]|[0-9]{2,}).*|1\.(([0-9]{2,}).*|[1-9]\.([0-9]{3,}|[0-9]{2,}|[7-9]))) but it doesn't match 1.2.0
You could use
^(?:1\.(?:1\.(?:[789]|[1-9]\d+)|(?:[1-9]\d+|[2-9])\.\d+)|(?:[1-9]\d+|[2-9])\.\d+\.\d+)$
The pattern matches:
^ Start of string(?: Non capture group
1\. Match 1.(?: Non capture group
1\. Match 1.(?:[789]|[1-9]\d+) Match either 7 8 9 or 10+| Or(?:[1-9]\d+|[2-9]) 10+ or 2-9\.\d+ Match . and 1+ digits 0-9) Close non capture group| Or(?: Non capture group
[1-9]\d+ 10+| Or[2-9] Match 2-9) Close non capture grouop\.\d+\.\d+ Match . 1+ digits . 1+ digits) Close outer non capture group$ End of string