What is the data type of text[i]?

Question

I'm trying to count the number of words in a string entered by the user with this custom function:

int count_words(char* text)
{
   int wc = 0;
   for(int i = 0,k = strlen(text); i<k;i++)
   {
      if(strcmp(" ",text[i]) ==0 || strcmp(".",text[i]) ==0 || strcmp("!",text[i]) ==0 || strcmp("?",text[i]) ==0 || strcmp(",",text[i]) ==0)
      {
          wc++;
      }
   }
    return wc+1;
}

but I keep getting this error:

re.c:59:21: error: incompatible integer to pointer conversion passing 'char' to parameter of type 'const char *'; take the address with & [-Werror,-Wint-conversion]
      if(strcmp(" ",text[i]) ==0 || strcmp(".",text[i]) ==0 || strcmp("!",text[i]) ==0 || strcmp("?",text[i]) ==0 || strcmp(",",text[i]) ==0)
                    ^~~~~~~
                    &

re.c:59:48: error: incompatible integer to pointer conversion passing 'char' to parameter of type 'const char *'; take the address with & [-Werror,-Wint-conversion]
      if(strcmp(" ",text[i]) ==0 || strcmp(".",text[i]) ==0 || strcmp("!",text[i]) ==0 || strcmp("?",text[i]) ==0 || strcmp(",",text[i]) ==0)
                                               ^~~~~~~
                                               &

What is really happening?

Answer 1

strcmp takes char * (string) not a single char. It's better if you use strtok` to count the number of words in a string.

Here's a simple example

#include <stdio.h>
#include <string.h>

int main(void) {

  char arr[] = "Temp hello bye! No way. Yes";
  char *delimeters = " !.";

  char *token = strtok(arr, delimeters);
  int count = 0;

  while (token != NULL) {
    count++;
    token = strtok(NULL, delimeters);
  }
  printf("Words = %d", count);

  return 0;
}

You can use strpbrk instead of strtok as well.