I am trying to get the name of the resource, I will share with you the regexr url
My actual regular expression: ([^/]+)(?=\..*)
My example: https://res-3.cloudinary.com/ngxcoder/image/upload/f_auto,q_auto/v1/blog-images/5oonz9.jpg
I'm trying to get just 5oonz9
I tried to include $, but I don't know why it doesn't work
You can use:
^.+\/(.+)\..+$
^.+
- From the start, match as many characters as possible\/
- Match a literal /
.(.+)
- Match one or more characters and capture them in a group\.
- Match a literal .
.+$
- Match one or more characters at the end of the string (the extension)Live demo here.