--Python What's wrong in this code?
a=int(input('enter a number'))
b=list(range(1,11))
if a not in b:
int(input('enter a number'))
else :
print('ok')
output:
enter a number 89
enter a number 8
Please explain a bit further what it is you're trying to do, if you're trying to output "OK" for the second input of '8', then you need to change the logic of this code.
a=int(input('enter a number'))
this line prints "enter a number" then your if statement checks if its within b but if it's not it prints "enter a number" again without doing anything with it, as seen in the next line:
int(input('enter a number'))
try using a for loop or while loop if you want your code to run through the if-else blocks more than once.
EDIT: try this code:
print('enter a number')
a=int(input())
while a not in range(1,11):
print('enter a number')
a=int(input())
else :
print('ok')