how to get original numbers from a list after computing the difference between to consecutive numbers

Question

{0: [41, 42, 183, 186, 471, 493, 639, 642, 732, 734], 1: [477, 489, 490]}

consider I have a dictionary with a list as values.

I want to find the difference between two consecutive numbers in the list and if their difference is less than, say 40, I want to fetch the second consecutive number of those two numbers taken into consideration and store all such kinds of numbers in a list.

Can anyone please help me with this.

Answer 1

One way to approach this:

data = {0: [41, 42, 183, 186, 471, 493, 639, 642, 732, 734], 1: [477, 489, 490]}
x = 40

{k: [b for a, b in zip(v, v[1:]) if a + x > b] for k, v in data.items()}
# {0: [42, 186, 493, 642, 734], 1: [489, 490]}

Or for a flat list:

[b for v in data.values() for a, b in zip(v, v[1:]) if a + 40 > b]
# [42, 186, 493, 642, 734, 489, 490]