I have some problems with calculating of confusion matrix. I have created three sets of points by multivariate normal distibution:
library('MASS')
library('ggplot2')
library('reshape2')
library("ClusterR")
library("cluster")
library("dplyr")
library ("factoextra")
library("dendextend")
library("circlize")
mu1<-c(1,1)
mu2<-c(1,-9)
mu3<-c(-7,-2)
sigma1<-matrix(c(1,1,1,2), nrow=2, ncol=2, byrow = TRUE)
sigma2<-matrix(c(1,-1,-1,2), nrow=2, ncol=2, byrow = TRUE)
sigma3<-matrix(c(2,0.5,0.5,0.3), nrow=2, ncol=2, byrow = TRUE)
simulation1<-mvrnorm(100,mu1,sigma1)
simulation2<-mvrnorm(100,mu2,sigma2)
simulation3<-mvrnorm(100,mu3,sigma3)
X<-rbind(simulation1,simulation2,simulation3)
colnames(X)<-c("x","y")
X<-data.frame(X)
I have also constructed clusters using k-means clustering and hierarchical clustering with k initial centers (k=3):
//k-means clustering
k<-3
B<-kmeans(X, centers = k, nstart = 10)
x_cluster = data.frame(X, group=factor(B$cluster))
ggplot(x_cluster, aes(x, y, color = group)) + geom_point()
//hierarchical clustering
single<-hclust(dist(X), method = "single")
clusters2<-cutree(single, k = 3)
fviz_cluster(list (data = X, cluster=clusters2))
How can I calculate confusion matrix for full dataset(X) using table in both of these cases?
Using your data, insert set.seed(42)
just before you create sigma1
so that we have a reproducible example. Then after you created X
:
X.df <- data.frame(Grp=rep(1:3, each=100), x=X[, 1], y=X[, 2])
k <- 3
B <- kmeans(X, centers = k, nstart = 10)
table(X.df$Grp, B$cluster)
#
# 1 2 3
# 1 1 0 99
# 2 0 100 0
# 3 100 0 0
Original group 1 is identified as group 3 with one specimen assigned to group 1. Original group 2 is assigned to group 2 and original group 3 is assigned to group 1. The group numbers are irrelevant. The classification is perfect if each row/column contains all values in a single cell. In this case only 1 specimen was missplaced.
single <- hclust(dist(X), method = "single")
clusters2 <- cutree(single, k = 3)
table(X.df$Grp, clusters2)
# clusters2
# 1 2 3
# 1 99 1 0
# 2 0 0 100
# 3 0 100 0
The results are the same, but the cluster numbers are different. One specimen from the original group 1 was assigned to the same group as the group 3 specimens. To compare these results:
table(Kmeans=B$cluster, Hierarch=clusters2)
# Hierarch
# Kmeans 1 2 3
# 1 0 101 0
# 2 0 0 100
# 3 99 0 0
Notice that each row/column contains only one cell that is nonzero. The two cluster analyses agree with one another even though the cluster designations differ.
D <- lda(Grp~x + y, X.df)
table(X.df$Grp, predict(D)$class)
#
# 1 2 3
# 1 99 0 1
# 2 0 100 0
# 3 0 0 100
Linear discriminant analysis tries to predict the specimen number given the values of x
and y
. Because of this, the cluster numbers are not arbitrary and the correct predictions all fall on the diagonal of the table. This is what is usually described as a confusion matrix.