I have a csv file that contains a bunch of data with one of the columns being date. I am trying to extract all lines that have dates in a specific year and save it into a new file.
The format of file is like this with the date and time in the second column:
000000000,10/04/2021 02:10:15 AM,.....
So far I tried:
grep -E ^2020 data.csv >> temp.csv
But it just produced an empty temp list. Any ideas on how I can do this?
One potential solution is with awk
:
awk -F"," '$2 ~ /\/2020 /' data.csv > temp.csv
Another potential option is with grep
:
grep "\/2020 " data.csv > temp.csv
However, the grep
solution may detect "/2020 " elsewhere in the file, rather than in column 2.