"in" operator chaining ( True in [True] in [True] OUTPUT: False )

Question

I'm trying to figure out in what order this code runs:

print( True in [True] in [True] )
False

even though:

print( ( True in [True] ) in [True] )
True

and:

print( True in ( [True] in [True] ) )
TypeError

If the first code is neither of these two last ones, then what?

Answer 1

in is comparing with chaining there so

True in [True] in [True]

is equivalent to (except middle [True] is evaluated once)

(True in [True]) and ([True] in [True])

which is

True and False

which is

False

This is all similar to

2 < 4 < 12

operation which is equivalent to (2 < 4) and (4 < 12).