I'm trying to access a property of the mainSubRollout
for the order the sub rollouts are in.
After running the code below and dragging Sub 2 rollout to the top like the image and checking mainRolTest.mainSubRollout.rollouts
it always returns #(Rollout:subRollout1, Rollout:subRollout2)
even though the displayed order of the rollouts are not the same.
How can I access this order in which they are currently displayed?
A result for the image should be: #(Rollout:subRollout2, Rollout:subRollout1)
try destroyDialog mainRolTest catch()
(
rollout subRollout1 "Sub 1" autoLayoutOnResize:true
(
button theButton1 "Fake Button 1"
)
rollout subRollout2 "Sub 2" autoLayoutOnResize:true
(
button theButton2 "Fake Button 2"
)
rollout mainRolTest "..."
(
button btn_close "X" align:#right offset:[13,-5]
SubRollout mainSubRollout "" height:133 width:150 pos:[0,20]
on btn_close pressed do destroydialog mainRolTest
)
createDialog mainRolTest 150 133 style:#() lockHeight:true lockWidth:true
AddSubRollout mainRolTest.mainSubRollout subRollout1
AddSubRollout mainRolTest.mainSubRollout subRollout2
)
-- This always returns #(Rollout:subRollout1, Rollout:subRollout2)
-- Even though the order of the rollouts are not the same
-- How can i access this info?
mainRolTest.mainSubRollout.rollouts
You can always use their actual position:
fn sortByY A B = (windows.getWindowPos A.hWnd).y - (windows.getWindowPos B.hWnd).y
rollouts = #() + mainRolTest.mainSubRollout.rollouts
qSort rollouts sortByY --> 'rollouts' will now be sorted based on Y
If you want the index and don't mind a bit of .NET, it can also be done this way:
iGlobal = (dotNetClass "Autodesk.Max.GlobalInterface").Instance
rollupContainer = iGlobal.GetIRollup (UIAccessor.GetParentWindow mainRolTest.mainSubRollout.rollouts[1].hwnd)
rollupContainer.GetPanelIndex mainRolTest.mainSubRollout.rollouts[2].hwnd
For completeness sake, you can do it through the Qt, too:
QtWidgets = python.import "PySide2.QtWidgets"
rolloutWidget = QtWidgets.QWidget.find (UIAccessor.GetParentWindow mainRolTest.mainSubRollout.rollouts[1].hwnd)
((rolloutWidget.parent()).layout()).indexOf rolloutWidget