How to convert 3650 columns (temperature) from Kelvin to Celsius?

I have a data frame with 10 years of daily temperature data. I want to convert all the values to Celsius. So I have 3.653 columns and 500 rows.

A sample of my data looks like below:

    
Location_ID     day1_2010     day2_2010     day3_2010    day4_2010 
------------------------------------------------------------------
1345             301             302         345          320
2375             305             302         345          320
3126             311             299         305          320

Solution

Just subtract from all columns but the ID column 273.15.

DF[-1] <- DF[-1] - 273.15
DF
#   Location_ID day1_2010 day2_2010 day3_2010 day4_2010
# 1        1345     27.85     28.85     71.85     46.85
# 2        2375     31.85     28.85     71.85     46.85
# 3        3126     37.85     25.85     31.85     46.85

Data

DF <- structure(list(Location_ID = c(1345L, 2375L, 3126L), day1_2010 = c(301L, 
305L, 311L), day2_2010 = c(302L, 302L, 299L), day3_2010 = c(345L, 
345L, 305L), day4_2010 = c(320L, 320L, 320L)), class = "data.frame", row.names = c(NA, 
-3L))