I have a dictionary in a Python code like this:
S = {(x0): 'omicron', (x1): 'a', (x2): 'ab', (x3): 'abbr', (x4): 'abr', (x5): 'abrf', (x6): 'abrfa', (x7): 'af', '(x8)': 'afc'}
I would like to check which key has its corresponding dictionary with the highest numer of letters, except for the one that has 'omicron'. The answer in this example should be: (x6), because it has a dictionary with 5 letters, more than any other key, and not counting (x0):'omicron'.
Is there an efficient way to do this? Thank you.
You could use the key parameter of max:
res = max(S, key=lambda x: (S[x] != 'omicron', len(S[x])))
print(res)
Output
(x6)
This will make the keys that the value is different than 'omicron'
have a higher value than one that are equals (1 > 0). For those keys that do not have 'omicron'
value use the length as a tie-breaker.