how to get o/p as {"Chennai": ["Ram", "stephen"], "Mumbai": "Laxman"} for given i/p = {"Ram": "Chennai", "Laxman": "Mumbai", "stephen": "Chennai"}

Question

I am trying to use defaultdict function here but that does not seem to work

s = {"Ram": "Chennai", "Laxman": "Mumbai", "stephen": "Chennai"} 
d = defaultdict(list)
for k, v in s:
    d[k].append(v)
sorted(d.items())
print(d)

Answer 1

this should work for you:

from collections import defaultdict


s = {"Ram": "Chennai", "Laxman": "Mumbai", "stephen": "Chennai"} 
d = defaultdict(list)
for k, v in s.items():
    d[v].append(k)

sorted(d.items())
print(d)

Output:

defaultdict(<class 'list'>, {'Chennai': ['Ram', 'stephen'], 'Mumbai': ['Laxman']})