issue in intialising character array from the structure through an array object

Question

i am getting an issue while initialising the character array in the structure through the structure object

#include <iostream>
    #include <string.h>
    using namespace std;
    struct emp
    {
        int age;
        char name[10];
    };
    int main()
    {
        struct emp v[2];
    
    List item
    
        v[0].age = 9;
        v[0].name[] = "name1"; <-this is where i am getting error
        v[1].age = 10;
        v[1].name[]= "name2"; <-this is where i am getting error
        for (int i = 0; i < 2; i++)
        {
            cout << v[i].age << " " << v[i].name<<endl;
        }
    
        return 0;
    }

Answer 1

For starters there is at least a typo

    v[0].name[] = "name1"; <-this is where i am getting error
            ^^^^ 
    v[1].name[]= "name2"; <-this is where i am getting error
            ^^^^

Arrays do not have the assignment operator. So these assignment statements

v[0].name[] = "name1";
v[1].name[]= "name2"; 

are incorrect syntactically and semantically.

You could initialize the elements of the array when it is declared.

For example

struct emp v[2] =
{
    { 9, "name1" },
    { 10, "name2" }
};

Otherwise you could use the standard string function strcpy. For example

#include <cstring>

//...
v[0].age = 9;
strcpy( v[0].name, "name1" );
v[1].age = 10;
strcpy( v[1].name, "name2" );

Another approach is to use class std::string instead of the character array. For example

#include <string>

// ...
struct emp
{
    int age;
    std::string name;
};

int main()
{
    struct emp v[2];

    v[0].age = 9;
    v[0].name = "name1";
    v[1].age = 10;
    v[1].name= "name2";
    for (int i = 0; i < 2; i++)
    {
        cout << v[i].age << " " << v[i].name<<endl;
    }

    return 0;
}

Pay attention to that instead of the ordinary for loop you could use the range-based for loop.

For example

for ( const auto &item : v )
{
    cout << item.age << " " << item.name << endl;
}