Compare all elements of list between themselves

Question

How do I count the occurrences of tuples in a list, regardless of the order of the tuple's items? For example;

the_list = [
    (one, two, three),
    (two, three, four),
    (one, three, two),
    (one, two, three),
    (four, two, one),
]

In the list above I want (one, two, three) and (one, three, two) to be equal and be counted as the same thing.

Answer 1

You can use a counter and sort them before you start counting

thelist = [(1,2,3), (2,3,4), (1,3,2), (1,2,3), (4,2,1)]
from collections import Counter
Counter(tuple(sorted(x)) for x in thelist)

Counter({(1, 2, 3): 3, (2, 3, 4): 1, (1, 2, 4): 1})