How to match a string that a specific word doesn't comes before it?

Question

I trying to match the string ARIBABA only if .get doesn't comes before it.

Example:

ARIBABA = config.get('SOMETHING', 'ARIBABA').lower()

I've tried this (down below) but it just doesn't match anything.

^(.get)\bARIBABA\b

Answer 1

You must use PyPi regex library here:

import regex
s = "ARIBABA = config.get('SOMETHING', 'ARIBABA').lower()"
p = r"(?<!\.get\b.*)\bARIBABA\b"
print(regex.findall(p, s))

See Python proof.

EXPLANATION

--------------------------------------------------------------------------------
  (?<!                     look behind to see if there is not:
--------------------------------------------------------------------------------
    \.                       '.'
--------------------------------------------------------------------------------
    get                      'get'
--------------------------------------------------------------------------------
    \b                       the boundary between a word char (\w)
                             and something that is not a word char
--------------------------------------------------------------------------------
    .*                       any character except \n (0 or more times
                             (matching the most amount possible))
--------------------------------------------------------------------------------
  )                        end of look-behind
--------------------------------------------------------------------------------
  \b                       the boundary between a word char (\w) and
                           something that is not a word char
--------------------------------------------------------------------------------
  ARIBABA                  'ARIBABA'
--------------------------------------------------------------------------------
  \b                       the boundary between a word char (\w) and
                           something that is not a word char