We have a xml which looks like below
<?xml version="1.0" encoding="UTF-8" standalone="yes"?>
<GeneratorRun>
<param>
<comGrp name="Abc">
<component name="A">
<genFiles>
<file location="xyz/a/b/x.h" checksum="1558926677"/>
<file location="xyz/a/b/y.h" checksum="2621886660"/>
</genFiles>
</component>
<component name="B">
<genFiles>
<file location=""xyz/a/b/z.h" checksum="1558926677"/>
</genFiles>
</component>
</comGrp>
</param>
I need to get all file location information which are under genFiles. WHats the experession for the same.
What I tries so far is below which didn't give the result
GPathResult xmlContent = new XmlSlurper().parse(config.genSourceRootDir.resolve('par.xml').toFile())
List<String> generatedFiles = xmlContent.'**'[email protected]()
You need to first find the nodes, then query their attributes
something like this:
List<String> generatedFiles = xmlContent.'**'
.findAll { it.name() == 'genFiles' }
.file*.collectMany { [it.@location] }.flatten()