How to get the URL from the given redirect deeplink string?
For example, if I have a deeplink string as
myapp://open-browser/https://mydaily.dev/JOURNAL/home?id=123e4567-e89b-12d3-a456-426655440000&source=01&channel_id=HOME
I would like to get the return result as
https://mydaily.dev/JOURNAL/home?id=123e4567-e89b-12d3-a456-426655440000&source=01&channel_id=HOME
I tried several methods from Apple documentation
Accessing the Parts of a URL,
the closest one was to combine path
and query
like below screenshot
Does anyone have a better way to do this?
I get your question, I think you want to get only the url starting from https://
, please correct me.
If so I think I could remove the deeplink url scheme myapp://
and the host open-browser/
like
let url = "myapp://open-browser/https://mydaily.dev/JOURNAL/home?id=123e4567-e89b-12d3-a456-426655440000&source=01&channel_id=HOME"
let deeplinkBase = "myapp://open-browser/"
let newUrl = url.absoluteString.replacingOccurrences(of: deeplinkBase, with: "")
Then you could use the newUrl
as you like since we got the expected result now
https://mydaily.dev/JOURNAL/home?id=123e4567-e89b-12d3-a456-426655440000&source=01&channel_id=HOME
My example for the deeplinkBase
string is hardcoded, but I guess you could use enums or any handlers for it later.