Remove content with parentheses under multiple conditions in Python

Question

Given a list as follows:

l = ['hydrogenated benzene (purity: 99.9 density (g/cm3), produced in ZB): SD', 
    'Car board price (tax included): JT Port', 
    'Ex-factory price (low-end price): Triethanolamine (85% commercial grade): North'
    ]

I would like to get the expected result as follows:

['hydrogenated benzene: SD', 'Car board price: JT Port', 'Ex-factory price: Triethanolamine: North']

With code below:

def remove_extra(content):
    pat1 = '[\s]'  # remove space
    pat2 = '\(.*\)' # remove content within parentheses
    combined_pat = r'|'.join((pat2, pat3))
    return re.sub(combined_pat, '', str(content))
[remove_extra(item) for item in l]

It generates:

['hydrogenated benzene : SD',
 'Car board price : JT Port',
 'Ex-factory price : North']

As you may notice, the last element of result 'Ex-factory price : North' is not as expected, how could I acheive what I need? Thanks.

Answer 1

You can modify linked solution with \s* for remove optionaly spaces before (:

#https://stackoverflow.com/a/37538815/2901002 
def remove_text_between_parens(text):
    n = 1  # run at least once
    while n:
        text, n = re.subn(r'\s*\([^()]*\)', '', text) #remove non-nested/flat balanced parts
    return text

a = [remove_text_between_parens(item) for item in l]
print (a)

['hydrogenated benzene: SD', 
 'Car board price: JT Port', 
 'Ex-factory price: Triethanolamine: North']