I'm using pyttsx3 to make a talking bot . and it work
import pyttsx3
f = pyttsx3.init()
a = input("type something: ")
if a == "hello":
print(f.say("Hi How are you"))
f.runAndWait()
but if I want the code to repeat the operation when ever its end I mean if I typed something and got the respond I will get another "type something" input without duplicate the code like this
import pyttsx3
f = pyttsx3.init()
a = input("type something: ")
if a == "hello":
print(f.say("Hi How are you"))
f.runAndWait()
b = input("type something: ")
if b == "hi":
print(f.say("Hi"))
f.runAndWait()
c = input("type something: ")
if c == "hey":
print(f.say("hi hows going"))
f.runAndWait()
i tried making a loop but didn't work
import pyttsx3
f = pyttsx3.init()
a = input("type something: ")
if a == "hello":
print(f.say("Hi How are you"))
for a in f:
print(a)
f.runAndWait()
So its going to ask me the a input again and again with no need to duplicate the code
I think it should work, I really didn't understand your question, but this is closest to what you asked for
import pyttsx3
f = pyttsx3.init()
while True:
a = input("type something: ")
if a == "hello":
print(f.say("Hi how are you?"))
elif a == "hi":
print(f.say("Hi"))
elif a == "hey":
print(f.say("hi hows going"))
f.runAndWait()
or if you want to try functions you can try:
import pyttsx3
f = pyttsx3.init()
while True:
nameoffunction()
def nameoffunction():
a = input("type something: ")
if a == "hello":
print(f.say("Hi how are you?"))
elif a == "hi":
print(f.say("Hi"))
elif a == "hey":
print(f.say("hi hows going"))
f.runAndWait()