I was messing around with Python when I found this behavior I can't really make sense of it. Code is the following:
x = ['A','B','C','D']
x = str(x)
y = "ABCD"
print(f"x = {x} \nx.find('B') is: {x.find('B')}\n\n")
print(f"y = {x} \ny.find('B') is: {y.find('B')}\n\n")
print(x)
print(y)
print(type(x)==type(y))
and the output on the console is:
x = ['A', 'B', 'C', 'D']
x.find('B') is: 7
y = ['A', 'B', 'C', 'D']
y.find('B') is: 1
['A', 'B', 'C', 'D']
ABCD
True
Things I don't fully understand are: Why x and y are showed as lists when printed in a formatted string?
Why when using simply print(x) or print(y) the ways of printing are different, even though type(x) == type(y)?
And specially why x.find('B') is 7, when the length of the string/list is 4, while y.find('B') works as expected?
Probably a trivial question but I didn't find something similar on the site. Thanks!
The reason your print(y) output looks weird is because you're actually passing x to print. As well, what you're seeing with x.find('B') is happening because you're converting 'x' to a str. This doesn't give you a list, but instead a string that looks like "['A', 'B', 'C', 'D']". So here B really is the 7th index of the string