ID which consists of slug and uuid Django Rest Framework

Question

I want to identify my database items over id which consists of slug and uuid, so if two users add f.e. name of the item: "Mercedes A40", they will be stored in database with different ids f.e. "mercedes-a40-25b6e133" and "mercedes-a40-11ac4431".

What should I type inside my Product model in id field? How can I combine it?

id = models.UUIDField(primary_key=True, default=uuid.uuid4, editable=False)
slug = models.SlugField(max_length=250, unique_for_date='published')

Answer 1

You can store it with two fields: a UUIDField and a SlugField, and use both in the urls.py.

For example:

urlpatterns = [
    # ...,
    path('<slug:slug>-<uuid:uuid>/', some_view, name='name-of-the-view'),
    # …
]

then in the view, you can retrieve the data with:

from django.shortcuts import get_object_or_404

def some_view(request, slug, uuid):
    object = get_object_or_404(MyModel, slug=slug, id=uuid)
    # …

and for a given object you can convert it to a URL with:

class MyModel(models.Model):
    id = models.UUIDField(primary_key=True, default=uuid.uuid4, editable=False)
    slug = models.SlugField(max_length=250, unique_for_date='published')

    # …

    def get_absolute_url(self):
        return reverse('name-of-the-view', kwargs={'uuid': self.id, 'slug': self.slug})

or in the template with:

{% url 'name-of-the-view' uuid=object.id slug=object.slug %}